Create a new list based on responses and use it in another loop

Coding
1

Hi, I’m having problems creating a new list based on responses and use that in another loop. This is the last part of a multisession experiment. Subjects will first make yes/no memory judgments for each image (trials loop). Then I want to generate a new list based on their responses and use that list in the following pair associate learning (study loop).
Here is the builder view I have:

Screen Shot 2021-03-31 at 3.10.56 PM
Screen Shot 2021-03-31 at 3.10.56 PM2396×1512 244 KB

Here is the excel file of trials loop results:
Screen Shot 2021-03-31 at 3.12.21 PM
Screen Shot 2021-03-31 at 3.12.21 PM2302×412 176 KB

I want to create a list for studyloop based on the responses of the trials loop. The conceptual idea is that:
If testjudg.corr == 1 and type ==“target” and CorrectSource == 1, store the correspond “Stim” “name” “type” into list A.
If testjudge.corr=1 and oldsource.corr=0 and type=target and CorrectSource=3, store the “Stim” “name” “type” into list B.
Then I need randomly choose 5 items of list A and 5 items of list B to create new pair associates. In the study loop, subjects will see one item from list A on the left and one item from list B on the right and learn the pair relationship.
I’m really having difficulty in generating this new list for study. So any suggestions or demos will be very appreciated!

2

The way to store is to start with

listA=[]

Then listA.append([vars needed separated by command])

listA[0][0] is the first value for the first row.

3

Thank your advice! I have made code like this
if testresp.corr == 0 and type ==“target”:
listA.append([Stim, type, Correct])
print(listA)
And it gives me [[‘002.jpg’, ‘target’, ‘left’], [‘003.jpg’, ‘target’, ‘left’]].
But I’m wondering how can I use this list as condition file for another loop?

4

Your new loop needs a loop counter (because.thisN doesn’t work online) but no spreadsheet.

nReps should be set to the desired number of trials or a large number if you intend to break the loo in code.

In the loop you can the set the image to listA[loopIdx][0] or you could have thisTrial = listA.pop() to select and remove the last item and then use thisTrial[0] for the image.