Counterbalance - Across participants

[wakecarter]

Please note that the code will result in a particular UNeven distribution of participants to groups. Please see my previous post about this code.

Random assignment of participants to groups

Hi Jens, In words, you’ve written: if divisible by 1 else if divisible by 3 else if divisible by 2 else. Here are how the first 20 participants will be divided: 1; 5; 7; 11; 13; 17; 19 = 7 participants 2; 10; 14 = 3 participants 3; 6; 9; 15; 18 = 5 participants 4; 8; 12; 16; 20 = 5 participants Please correct me if you think I’ve got that wrong. Participant 0 (if you have one) would be allocated to group 4. My method is to divide by 4 and use the remainder which will equally be 0, 1, 2 or …