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Fixation cross duration various duration

I have an experimentation of n-back.

I have letter that appear for a maximum of 2.5 sec and then a fixation cross for 0.5 sec.

Right now: When the participant pressed on the keyboard, it ends the routine and go directly to the fixation cross. I have 60 letters so the experimentation would take at max 3 minutes, but it can be less if the participant pressed fast.

What I want : My experimentation should take 3 min at every time. So the fixation cross should stay for more than 0.5 sec if the participant answer fast.

Thanks for your help!

You need to unckeck the “Force end of Routine” in the Keyboard component

Thanks for your fast response.
But when I do that, I have my letter that stays on the screen for all the duration of the routine, but what I really want is that the fixation cross stays longer

Someone on an other forum got the answer. Thanks to @lindeloev I put it here if it can help someone.
That’s his reply :
"In your ‘trial’ routine, I would record the routine starting time. Then in the ‘fixation’ routine, I would wait until 3 secs have passed since that starting time.

So in ‘trial’ routine --> Code Component --> ‘begin trial’ tab:

trial_start = core.monotonicClock.getTime()

Then in the ‘fixation’ routine --> fixation cross component --> duration, enter:

$trial_start + 3 - core.monotonicClock.getTime()  # 3 secs later "