OS (e.g. Win10): macOS 11.6 PsychoPy version (e.g. 1.84.x): 2022.2.4 Standard Standalone? (y/n) If not then what?: y What are you trying to achieve?: skip a loop with two Routines Dear all, my experiment has a trial-by-trial cueing design, where participants perform one of three possible tasks…

Please could you show a screenshot of your code component?

Of course! [Screenshot 2022-11-11 at 12.20.59]

Add print(task) to the top to check what values of task you are actually getting. Pay particular attention to spaces. I’m guessing that your other print statement isn’t showing.

It does print both the right task and the other statement. The stimuli in “test” and “feedback” are not shown. But for some reason, I get a blank screen as long as test and feedback combined (4s), if task==‘LTM’ or task==‘STM_notest’. [Screenshot 2022-11-11 at 12.28.44]

Try putting the code in Each Frame. It shouldn’t be necessary but I think there was a bug in an earlier version that required that. Is your “use version “ blank?

My “use version” was blank, now I set it on “2022.2.4”, but it didn’t change anything. I added the code in Each Frame and no luck either.

Blank is generally better. To clarify, You ARE seeing the “No test in this trial” message come up? If so, I’m not sure why continueRoutine = False isn’t working for you but there is an alternative method that should work. [image] Create a code that skip a routine after that it has…

[image] wakecarter: No test in this trial Correct, I’m seeing the “No test in this trial” message in the runner. I have no idea why the countinueRoutine isn’t working, but the alternative method works! :slight_smile: Thank you so much.

I’ve just confirmed that continueRoutine = False does not work in 2022.2.x offline. It results in a blank screen for the normal duration of the routine. continueRoutine code | try it The expected behaviour is correct online. It also works offline if you set the version as 2022.1.4

This is to do with non-slip timing. Essentially, if you set continueRoutine = False during the frame loop, it takes note of the fact that the routine ended before the planned time so that the timer can be reset to 0 rather than having the expected duration subtracted (which we do for routines with a…

continueRoutine = false, but routine still running without stimuli

Builder

treelen November 14, 2022, 3:42pm 12

Do these two methods have any advantage in comparison to the one linked by @wakecarter?

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continueRoutine = false, but routine still running without stimuli

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